M=-2m^2+5m+1

Solution for M=-2m^2+5m+1 equation:

=-2M^2+5M+1

We move all terms to the left:

-(-2M^2+5M+1)=0

We get rid of parentheses

2M^2-5M-1=0

a = 2; b = -5; c = -1;
Δ = b2-4ac
Δ = -52-4·2·(-1)
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$M_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$M_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$M_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{33}}{2*2}=\frac{5-\sqrt{33}}{4}
$
$M_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{33}}{2*2}=\frac{5+\sqrt{33}}{4}
$